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revers_num
数字之和与它的取反可以被它们之间的差(绝对值)整除。比如 45 这个数字 (45+54)%|45-54| == 0,要求时输出第满足条件的第 n 个数字的值. 我用下面的代码实现了但是速度很慢,有什么办法可以优化么?
1
Python
•
CupCupFun
•
Jun 16, 2020
• Lastly replied by
necomancer
2
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